3.1468 \(\int \frac {1}{x^6 (a+b x^8)} \, dx\)

Optimal. Leaf size=277 \[ -\frac {b^{5/8} \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{-a}+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{-a}+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}+\frac {b^{5/8} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}+1\right )}{4 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \tanh ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {1}{5 a x^5} \]

[Out]

-1/5/a/x^5+1/4*b^(5/8)*arctan(b^(1/8)*x/(-a)^(1/8))/(-a)^(13/8)-1/4*b^(5/8)*arctanh(b^(1/8)*x/(-a)^(1/8))/(-a)
^(13/8)-1/8*b^(5/8)*arctan(-1+b^(1/8)*x*2^(1/2)/(-a)^(1/8))/(-a)^(13/8)*2^(1/2)-1/8*b^(5/8)*arctan(1+b^(1/8)*x
*2^(1/2)/(-a)^(1/8))/(-a)^(13/8)*2^(1/2)-1/16*b^(5/8)*ln((-a)^(1/4)+b^(1/4)*x^2-(-a)^(1/8)*b^(1/8)*x*2^(1/2))/
(-a)^(13/8)*2^(1/2)+1/16*b^(5/8)*ln((-a)^(1/4)+b^(1/4)*x^2+(-a)^(1/8)*b^(1/8)*x*2^(1/2))/(-a)^(13/8)*2^(1/2)

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Rubi [A]  time = 0.23, antiderivative size = 277, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 11, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.846, Rules used = {325, 300, 297, 1162, 617, 204, 1165, 628, 298, 205, 208} \[ -\frac {b^{5/8} \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{-a}+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{-a}+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}+\frac {b^{5/8} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}+1\right )}{4 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \tanh ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {1}{5 a x^5} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^6*(a + b*x^8)),x]

[Out]

-1/(5*a*x^5) + (b^(5/8)*ArcTan[(b^(1/8)*x)/(-a)^(1/8)])/(4*(-a)^(13/8)) + (b^(5/8)*ArcTan[1 - (Sqrt[2]*b^(1/8)
*x)/(-a)^(1/8)])/(4*Sqrt[2]*(-a)^(13/8)) - (b^(5/8)*ArcTan[1 + (Sqrt[2]*b^(1/8)*x)/(-a)^(1/8)])/(4*Sqrt[2]*(-a
)^(13/8)) - (b^(5/8)*ArcTanh[(b^(1/8)*x)/(-a)^(1/8)])/(4*(-a)^(13/8)) - (b^(5/8)*Log[(-a)^(1/4) - Sqrt[2]*(-a)
^(1/8)*b^(1/8)*x + b^(1/4)*x^2])/(8*Sqrt[2]*(-a)^(13/8)) + (b^(5/8)*Log[(-a)^(1/4) + Sqrt[2]*(-a)^(1/8)*b^(1/8
)*x + b^(1/4)*x^2])/(8*Sqrt[2]*(-a)^(13/8))

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 297

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 298

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(a/b),
2]]}, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &
&  !GtQ[a/b, 0]

Rule 300

Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(
a/b), 2]]}, Dist[r/(2*a), Int[x^m/(r + s*x^(n/2)), x], x] + Dist[r/(2*a), Int[x^m/(r - s*x^(n/2)), x], x]] /;
FreeQ[{a, b}, x] && IGtQ[n/4, 0] && IGtQ[m, 0] && LtQ[m, n/2] &&  !GtQ[a/b, 0]

Rule 325

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a*
c*(m + 1)), x] - Dist[(b*(m + n*(p + 1) + 1))/(a*c^n*(m + 1)), Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; Free
Q[{a, b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {1}{x^6 \left (a+b x^8\right )} \, dx &=-\frac {1}{5 a x^5}-\frac {b \int \frac {x^2}{a+b x^8} \, dx}{a}\\ &=-\frac {1}{5 a x^5}-\frac {b \int \frac {x^2}{\sqrt {-a}-\sqrt {b} x^4} \, dx}{2 (-a)^{3/2}}-\frac {b \int \frac {x^2}{\sqrt {-a}+\sqrt {b} x^4} \, dx}{2 (-a)^{3/2}}\\ &=-\frac {1}{5 a x^5}-\frac {b^{3/4} \int \frac {1}{\sqrt [4]{-a}-\sqrt [4]{b} x^2} \, dx}{4 (-a)^{3/2}}+\frac {b^{3/4} \int \frac {1}{\sqrt [4]{-a}+\sqrt [4]{b} x^2} \, dx}{4 (-a)^{3/2}}+\frac {b^{3/4} \int \frac {\sqrt [4]{-a}-\sqrt [4]{b} x^2}{\sqrt {-a}+\sqrt {b} x^4} \, dx}{4 (-a)^{3/2}}-\frac {b^{3/4} \int \frac {\sqrt [4]{-a}+\sqrt [4]{b} x^2}{\sqrt {-a}+\sqrt {b} x^4} \, dx}{4 (-a)^{3/2}}\\ &=-\frac {1}{5 a x^5}+\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {b^{5/8} \tanh ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {\sqrt {b} \int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{b}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{b}}+x^2} \, dx}{8 (-a)^{3/2}}-\frac {\sqrt {b} \int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{b}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{b}}+x^2} \, dx}{8 (-a)^{3/2}}-\frac {b^{5/8} \int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{b}}+2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{b}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{b}}-x^2} \, dx}{8 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{b}}-2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{b}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{b}}-x^2} \, dx}{8 \sqrt {2} (-a)^{13/8}}\\ &=-\frac {1}{5 a x^5}+\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {b^{5/8} \tanh ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {b^{5/8} \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 \sqrt {2} (-a)^{13/8}}\\ &=-\frac {1}{5 a x^5}+\frac {b^{5/8} \tan ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}+\frac {b^{5/8} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 \sqrt {2} (-a)^{13/8}}-\frac {b^{5/8} \tanh ^{-1}\left (\frac {\sqrt [8]{b} x}{\sqrt [8]{-a}}\right )}{4 (-a)^{13/8}}-\frac {b^{5/8} \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}+\frac {b^{5/8} \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{b} x+\sqrt [4]{b} x^2\right )}{8 \sqrt {2} (-a)^{13/8}}\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 395, normalized size = 1.43 \[ \frac {-8 a^{5/8}+10 b^{5/8} x^5 \sin \left (\frac {\pi }{8}\right ) \tan ^{-1}\left (\frac {\sqrt [8]{b} x \sec \left (\frac {\pi }{8}\right )}{\sqrt [8]{a}}-\tan \left (\frac {\pi }{8}\right )\right )+10 b^{5/8} x^5 \sin \left (\frac {\pi }{8}\right ) \tan ^{-1}\left (\frac {\sqrt [8]{b} x \sec \left (\frac {\pi }{8}\right )}{\sqrt [8]{a}}+\tan \left (\frac {\pi }{8}\right )\right )+10 b^{5/8} x^5 \cos \left (\frac {\pi }{8}\right ) \tan ^{-1}\left (\cot \left (\frac {\pi }{8}\right )-\frac {\sqrt [8]{b} x \csc \left (\frac {\pi }{8}\right )}{\sqrt [8]{a}}\right )-10 b^{5/8} x^5 \cos \left (\frac {\pi }{8}\right ) \tan ^{-1}\left (\frac {\sqrt [8]{b} x \csc \left (\frac {\pi }{8}\right )}{\sqrt [8]{a}}+\cot \left (\frac {\pi }{8}\right )\right )-5 b^{5/8} x^5 \cos \left (\frac {\pi }{8}\right ) \log \left (-2 \sqrt [8]{a} \sqrt [8]{b} x \sin \left (\frac {\pi }{8}\right )+\sqrt [4]{a}+\sqrt [4]{b} x^2\right )+5 b^{5/8} x^5 \cos \left (\frac {\pi }{8}\right ) \log \left (2 \sqrt [8]{a} \sqrt [8]{b} x \sin \left (\frac {\pi }{8}\right )+\sqrt [4]{a}+\sqrt [4]{b} x^2\right )+5 b^{5/8} x^5 \sin \left (\frac {\pi }{8}\right ) \log \left (-2 \sqrt [8]{a} \sqrt [8]{b} x \cos \left (\frac {\pi }{8}\right )+\sqrt [4]{a}+\sqrt [4]{b} x^2\right )-5 b^{5/8} x^5 \sin \left (\frac {\pi }{8}\right ) \log \left (2 \sqrt [8]{a} \sqrt [8]{b} x \cos \left (\frac {\pi }{8}\right )+\sqrt [4]{a}+\sqrt [4]{b} x^2\right )}{40 a^{13/8} x^5} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^6*(a + b*x^8)),x]

[Out]

(-8*a^(5/8) + 10*b^(5/8)*x^5*ArcTan[Cot[Pi/8] - (b^(1/8)*x*Csc[Pi/8])/a^(1/8)]*Cos[Pi/8] - 10*b^(5/8)*x^5*ArcT
an[Cot[Pi/8] + (b^(1/8)*x*Csc[Pi/8])/a^(1/8)]*Cos[Pi/8] - 5*b^(5/8)*x^5*Cos[Pi/8]*Log[a^(1/4) + b^(1/4)*x^2 -
2*a^(1/8)*b^(1/8)*x*Sin[Pi/8]] + 5*b^(5/8)*x^5*Cos[Pi/8]*Log[a^(1/4) + b^(1/4)*x^2 + 2*a^(1/8)*b^(1/8)*x*Sin[P
i/8]] + 10*b^(5/8)*x^5*ArcTan[(b^(1/8)*x*Sec[Pi/8])/a^(1/8) - Tan[Pi/8]]*Sin[Pi/8] + 10*b^(5/8)*x^5*ArcTan[(b^
(1/8)*x*Sec[Pi/8])/a^(1/8) + Tan[Pi/8]]*Sin[Pi/8] + 5*b^(5/8)*x^5*Log[a^(1/4) + b^(1/4)*x^2 - 2*a^(1/8)*b^(1/8
)*x*Cos[Pi/8]]*Sin[Pi/8] - 5*b^(5/8)*x^5*Log[a^(1/4) + b^(1/4)*x^2 + 2*a^(1/8)*b^(1/8)*x*Cos[Pi/8]]*Sin[Pi/8])
/(40*a^(13/8)*x^5)

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fricas [B]  time = 0.74, size = 524, normalized size = 1.89 \[ \frac {20 \, \sqrt {2} a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \arctan \left (-\frac {\sqrt {2} a^{8} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {5}{8}} - \sqrt {2} a^{8} \sqrt {\frac {a^{10} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{4}} + \sqrt {2} a^{5} b^{2} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{8}} + b^{4} x^{2}}{b^{4}}} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {5}{8}} - b^{3}}{b^{3}}\right ) + 20 \, \sqrt {2} a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \arctan \left (-\frac {\sqrt {2} a^{8} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {5}{8}} - \sqrt {2} a^{8} \sqrt {\frac {a^{10} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{4}} - \sqrt {2} a^{5} b^{2} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{8}} + b^{4} x^{2}}{b^{4}}} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {5}{8}} + b^{3}}{b^{3}}\right ) - 5 \, \sqrt {2} a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \log \left (a^{10} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{4}} + \sqrt {2} a^{5} b^{2} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{8}} + b^{4} x^{2}\right ) + 5 \, \sqrt {2} a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \log \left (a^{10} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{4}} - \sqrt {2} a^{5} b^{2} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{8}} + b^{4} x^{2}\right ) - 40 \, a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \arctan \left (-\frac {a^{8} x \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {5}{8}} - a^{8} \sqrt {\frac {a^{10} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{4}} + b^{4} x^{2}}{b^{4}}} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {5}{8}}}{b^{3}}\right ) + 10 \, a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \log \left (a^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{8}} + b^{2} x\right ) - 10 \, a x^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {1}{8}} \log \left (-a^{5} \left (-\frac {b^{5}}{a^{13}}\right )^{\frac {3}{8}} + b^{2} x\right ) - 16}{80 \, a x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^6/(b*x^8+a),x, algorithm="fricas")

[Out]

1/80*(20*sqrt(2)*a*x^5*(-b^5/a^13)^(1/8)*arctan(-(sqrt(2)*a^8*x*(-b^5/a^13)^(5/8) - sqrt(2)*a^8*sqrt((a^10*(-b
^5/a^13)^(3/4) + sqrt(2)*a^5*b^2*x*(-b^5/a^13)^(3/8) + b^4*x^2)/b^4)*(-b^5/a^13)^(5/8) - b^3)/b^3) + 20*sqrt(2
)*a*x^5*(-b^5/a^13)^(1/8)*arctan(-(sqrt(2)*a^8*x*(-b^5/a^13)^(5/8) - sqrt(2)*a^8*sqrt((a^10*(-b^5/a^13)^(3/4)
- sqrt(2)*a^5*b^2*x*(-b^5/a^13)^(3/8) + b^4*x^2)/b^4)*(-b^5/a^13)^(5/8) + b^3)/b^3) - 5*sqrt(2)*a*x^5*(-b^5/a^
13)^(1/8)*log(a^10*(-b^5/a^13)^(3/4) + sqrt(2)*a^5*b^2*x*(-b^5/a^13)^(3/8) + b^4*x^2) + 5*sqrt(2)*a*x^5*(-b^5/
a^13)^(1/8)*log(a^10*(-b^5/a^13)^(3/4) - sqrt(2)*a^5*b^2*x*(-b^5/a^13)^(3/8) + b^4*x^2) - 40*a*x^5*(-b^5/a^13)
^(1/8)*arctan(-(a^8*x*(-b^5/a^13)^(5/8) - a^8*sqrt((a^10*(-b^5/a^13)^(3/4) + b^4*x^2)/b^4)*(-b^5/a^13)^(5/8))/
b^3) + 10*a*x^5*(-b^5/a^13)^(1/8)*log(a^5*(-b^5/a^13)^(3/8) + b^2*x) - 10*a*x^5*(-b^5/a^13)^(1/8)*log(-a^5*(-b
^5/a^13)^(3/8) + b^2*x) - 16)/(a*x^5)

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giac [B]  time = 0.36, size = 453, normalized size = 1.64 \[ \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x + \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{4 \, a^{2} \sqrt {2 \, \sqrt {2} + 4}} + \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x - \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{4 \, a^{2} \sqrt {2 \, \sqrt {2} + 4}} - \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x + \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{4 \, a^{2} \sqrt {-2 \, \sqrt {2} + 4}} - \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x - \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{4 \, a^{2} \sqrt {-2 \, \sqrt {2} + 4}} - \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} + x \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{8 \, a^{2} \sqrt {2 \, \sqrt {2} + 4}} + \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} - x \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{8 \, a^{2} \sqrt {2 \, \sqrt {2} + 4}} + \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} + x \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{8 \, a^{2} \sqrt {-2 \, \sqrt {2} + 4}} - \frac {b \left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} - x \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{8 \, a^{2} \sqrt {-2 \, \sqrt {2} + 4}} - \frac {1}{5 \, a x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^6/(b*x^8+a),x, algorithm="giac")

[Out]

1/4*b*(a/b)^(3/8)*arctan((2*x + sqrt(-sqrt(2) + 2)*(a/b)^(1/8))/(sqrt(sqrt(2) + 2)*(a/b)^(1/8)))/(a^2*sqrt(2*s
qrt(2) + 4)) + 1/4*b*(a/b)^(3/8)*arctan((2*x - sqrt(-sqrt(2) + 2)*(a/b)^(1/8))/(sqrt(sqrt(2) + 2)*(a/b)^(1/8))
)/(a^2*sqrt(2*sqrt(2) + 4)) - 1/4*b*(a/b)^(3/8)*arctan((2*x + sqrt(sqrt(2) + 2)*(a/b)^(1/8))/(sqrt(-sqrt(2) +
2)*(a/b)^(1/8)))/(a^2*sqrt(-2*sqrt(2) + 4)) - 1/4*b*(a/b)^(3/8)*arctan((2*x - sqrt(sqrt(2) + 2)*(a/b)^(1/8))/(
sqrt(-sqrt(2) + 2)*(a/b)^(1/8)))/(a^2*sqrt(-2*sqrt(2) + 4)) - 1/8*b*(a/b)^(3/8)*log(x^2 + x*sqrt(sqrt(2) + 2)*
(a/b)^(1/8) + (a/b)^(1/4))/(a^2*sqrt(2*sqrt(2) + 4)) + 1/8*b*(a/b)^(3/8)*log(x^2 - x*sqrt(sqrt(2) + 2)*(a/b)^(
1/8) + (a/b)^(1/4))/(a^2*sqrt(2*sqrt(2) + 4)) + 1/8*b*(a/b)^(3/8)*log(x^2 + x*sqrt(-sqrt(2) + 2)*(a/b)^(1/8) +
(a/b)^(1/4))/(a^2*sqrt(-2*sqrt(2) + 4)) - 1/8*b*(a/b)^(3/8)*log(x^2 - x*sqrt(-sqrt(2) + 2)*(a/b)^(1/8) + (a/b
)^(1/4))/(a^2*sqrt(-2*sqrt(2) + 4)) - 1/5/(a*x^5)

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maple [C]  time = 0.01, size = 36, normalized size = 0.13 \[ -\frac {\ln \left (-\RootOf \left (b \,\textit {\_Z}^{8}+a \right )+x \right )}{8 a \RootOf \left (b \,\textit {\_Z}^{8}+a \right )^{5}}-\frac {1}{5 a \,x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^6/(b*x^8+a),x)

[Out]

-1/5/a/x^5-1/8/a*sum(1/_R^5*ln(-_R+x),_R=RootOf(_Z^8*b+a))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {-\frac {1}{8} \, b {\left (\frac {2 \, \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x + \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{a \sqrt {2 \, \sqrt {2} + 4}} + \frac {2 \, \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x - \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{a \sqrt {2 \, \sqrt {2} + 4}} - \frac {2 \, \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x + \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{a \sqrt {-2 \, \sqrt {2} + 4}} - \frac {2 \, \left (\frac {a}{b}\right )^{\frac {3}{8}} \arctan \left (\frac {2 \, x - \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}}}\right )}{a \sqrt {-2 \, \sqrt {2} + 4}} - \frac {\left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} + x \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{a \sqrt {2 \, \sqrt {2} + 4}} + \frac {\left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} - x \sqrt {\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{a \sqrt {2 \, \sqrt {2} + 4}} + \frac {\left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} + x \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{a \sqrt {-2 \, \sqrt {2} + 4}} - \frac {\left (\frac {a}{b}\right )^{\frac {3}{8}} \log \left (x^{2} - x \sqrt {-\sqrt {2} + 2} \left (\frac {a}{b}\right )^{\frac {1}{8}} + \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}{a \sqrt {-2 \, \sqrt {2} + 4}}\right )}}{a} - \frac {1}{5 \, a x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^6/(b*x^8+a),x, algorithm="maxima")

[Out]

-b*integrate(x^2/(b*x^8 + a), x)/a - 1/5/(a*x^5)

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mupad [B]  time = 0.15, size = 118, normalized size = 0.43 \[ -\frac {1}{5\,a\,x^5}-\frac {{\left (-b\right )}^{5/8}\,\mathrm {atan}\left (\frac {{\left (-b\right )}^{1/8}\,x}{a^{1/8}}\right )}{4\,a^{13/8}}-\frac {{\left (-b\right )}^{5/8}\,\mathrm {atan}\left (\frac {{\left (-b\right )}^{1/8}\,x\,1{}\mathrm {i}}{a^{1/8}}\right )\,1{}\mathrm {i}}{4\,a^{13/8}}+\frac {\sqrt {2}\,{\left (-b\right )}^{5/8}\,\mathrm {atan}\left (\frac {\sqrt {2}\,{\left (-b\right )}^{1/8}\,x\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )}{a^{1/8}}\right )\,\left (\frac {1}{8}-\frac {1}{8}{}\mathrm {i}\right )}{a^{13/8}}+\frac {\sqrt {2}\,{\left (-b\right )}^{5/8}\,\mathrm {atan}\left (\frac {\sqrt {2}\,{\left (-b\right )}^{1/8}\,x\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )}{a^{1/8}}\right )\,\left (\frac {1}{8}+\frac {1}{8}{}\mathrm {i}\right )}{a^{13/8}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^6*(a + b*x^8)),x)

[Out]

(2^(1/2)*(-b)^(5/8)*atan((2^(1/2)*(-b)^(1/8)*x*(1/2 - 1i/2))/a^(1/8))*(1/8 - 1i/8))/a^(13/8) - ((-b)^(5/8)*ata
n(((-b)^(1/8)*x)/a^(1/8)))/(4*a^(13/8)) - ((-b)^(5/8)*atan(((-b)^(1/8)*x*1i)/a^(1/8))*1i)/(4*a^(13/8)) - 1/(5*
a*x^5) + (2^(1/2)*(-b)^(5/8)*atan((2^(1/2)*(-b)^(1/8)*x*(1/2 + 1i/2))/a^(1/8))*(1/8 + 1i/8))/a^(13/8)

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sympy [A]  time = 0.58, size = 36, normalized size = 0.13 \[ \operatorname {RootSum} {\left (16777216 t^{8} a^{13} + b^{5}, \left (t \mapsto t \log {\left (\frac {512 t^{3} a^{5}}{b^{2}} + x \right )} \right )\right )} - \frac {1}{5 a x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**6/(b*x**8+a),x)

[Out]

RootSum(16777216*_t**8*a**13 + b**5, Lambda(_t, _t*log(512*_t**3*a**5/b**2 + x))) - 1/(5*a*x**5)

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